A. What impulse must be imparted to a golf ball of mass 0.043 kg to give it a velocity of 48.8 m/s? I think the answer is 2.09 kg m/s but im really confused on this next part B
B. If the golf club is in contact with the ball as it is accelerated over an interval of 1.11 cm, estimate the average force exerted on the ball by the club.
A) Impulse (I) = delta P = m x delta v = 0.043 x 48.8 = 2.09 N-s
B) By v^2 = u^2 + 2as
=>(48.8)^2 = 0 + 2 x a x (1.11 x 10^-2)
=>a = 214544.14 m/s^2
Thus By F = ma
=>F = 0.043 x 214544.14 = 9225.40 N
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A) Impulse (I) = delta P = m x delta v = 0.043 x 48.8 = 2.09 N-s
B) By v^2 = u^2 + 2as
=>(48.8)^2 = 0 + 2 x a x (1.11 x 10^-2)
=>a = 214544.14 m/s^2
Thus By F = ma
=>F = 0.043 x 214544.14 = 9225.40 N
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